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  1. #21
    Join Date
    Aug 2000
    Location
    Placitas, New Mexico, USA
    Posts
    41,548

    Default Re: Isometric grid set at 26 degrees

    Just because I am dense, and inquisitive, but why would you want the grid to be at 26 degrees instead of multiples of 15?

    Isometric grids and drawings are a simple method of simulating 3D perspective without the tedious vanishing points etc.

  2. #22
    Join Date
    Aug 2004
    Location
    Ukraine
    Posts
    3,904

    Default Re: Isometric grid set at 26 degrees

    Because it is easy to draw on the graph paper. See attached.
    This was not invented by Xara but was used for many years and possibly was even more often used than the true isometric.
    And it's not 26° but atan(0.5) ~ 26.565051177077989351572193720453°...
    Attached Thumbnails Attached Thumbnails Click image for larger version. 

Name:	iso2.png 
Views:	143 
Size:	1.6 KB 
ID:	70351  
    Last edited by covoxer; 07 March 2010 at 05:51 PM.
    John.

  3. #23
    Join Date
    Feb 2007
    Location
    UK
    Posts
    21,400

    Default Re: Isometric grid set at 26 degrees

    -------------------------------
    Nothing lasts forever...

  4. #24

    Default Re: Isometric grid set at 26 degrees

    Quote Originally Posted by covoxer
    And it's not 26° but atan(0.5) ~ 26.565051177077989351572193720453°
    For fun, I'll add the following equivalents.
    Attached Images Attached Images  

  5. #25
    Join Date
    Nov 2000
    Location
    Red Boiling Springs TN USA
    Posts
    19,208

    Default Re: Isometric grid set at 26 degrees

    Curtis either my calculator is broken or your formulae are inaccurate.
    Soquili
    a.k.a. Bill Taylor
    Bill is no longer with us. He died on 10 Dec 2012. We remember him always.
    My TG Album
    Last XaReg update

  6. #26

    Default Re: Isometric grid set at 26 degrees

    They work fine for me, Bill. Note that the symbol prior to the square-root-of-five is a division symbol, not a plus sign.
    Attached Images Attached Images  

  7. #27

    Default Re: Isometric grid set at 26 degrees

    Considering covoxer's graphic above, the slope of the line is 1:2. Given that a² + b² = c², c, the hypotenuse would be the square root of 5.

    The angle could be expressed as tan(a/b), sin(a/c), and cos(b/c).

  8. #28
    Join Date
    Nov 2000
    Location
    Red Boiling Springs TN USA
    Posts
    19,208

    Default Re: Isometric grid set at 26 degrees

    Curtis larger size doesn't change the formula, the sine of 1 divided by the square root of 5 does not yield anything near 26.565051177077989351572193720453°

    The square root of 5 is 2.2360679774997896964091736687313
    1 divided by 2.2360679774997896964091736687313 equals 0.44721359549995793928183473374626

    Sin(0.44721359549995793928183473374626) equals 0.0078052704465482364130100178763261

    The CoSine of 2 divided by the square root of 5 equals 0.99987815550651248138827984630394

    Neither are equal to 26.565....
    Soquili
    a.k.a. Bill Taylor
    Bill is no longer with us. He died on 10 Dec 2012. We remember him always.
    My TG Album
    Last XaReg update

  9. #29
    Join Date
    Aug 2000
    Location
    Placitas, New Mexico, USA
    Posts
    41,548

    Default Re: Isometric grid set at 26 degrees

    I'm really sorry I asked. I did not think that slide rules would be needed.

  10. #30

    Default Re: Isometric grid set at 26 degrees

    My head hurts...

 

 

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