Find/Replace feature for changing colors and color models

**alexbozhenov** · 19 June 2009, 04:22 AM

CorelDraw has excellent Find/Replace features, I've been asking for similar for years here. There are also quick find/Replace dialog for the entire color schemes (RGB to CMYK etc).

AI has handy options like "Select all objects with the same fill color", "...Line color" etc.

And now it also has a palette with all objects where you can select and change fills/line colors by every object individually or entirely drawing.

To deal with Xtreme's Name Gallery you have to always use named colors. But what if you have to use a Color Dropper to assign colors to your objects? Also, changing a color model from RGB to CMYK and whatever is not very trivial task in Xtreme (you have not just select color model from the DD menu, but also change any value to apply color model modification).

Thanks!

**steve.ledger** · 19 June 2009, 04:38 AM

+1

**Zupdude** · 19 June 2009, 04:50 AM

Ditto!

**Albacore** · 19 June 2009, 08:55 AM

Now I use that a lot in Illy so plus one for me as well.

**bcire68** · 23 June 2009, 01:34 PM

This would be very helpful for those of us that draw first and assign colors later. I am trying to break myself of that habit but it doesn't always work out that way.

Eric

**ss-kalm** · 23 June 2009, 04:40 PM

Agreed - "Change what colour?" <click> "To what colour?" <click> ........

**angelize** · 24 June 2009, 05:40 AM

This would be very useful to me if it had an option to change all colours in a selected drawing to shades of grey.

**steve.ledger** · 24 June 2009, 06:06 AM

Originally Posted by angelize

This would be very useful to me if it had an option to change all colours in a selected drawing to shades of grey.

There already is Frances, use the 'Hue' LE and drop the saturation to -100
The drawing remains an editable vector.
.
.

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**zz_young** · 24 June 2009, 07:55 AM

Originally Posted by sledger

There already is Frances, use the 'Hue' LE and drop the saturation to -100
The drawing remains an editable vector.
.
.

when the hue LE is used
all the shape will have a LE hue state
when the shapes are selected
it's color in the color panel is still the original color

**handrawn** · 24 June 2009, 08:41 AM

sorry Steve - that does not work

removing saturation can remove completely graduated tones, rather than converting them to visible grey[scale]

and zz_young's point is also true