...Accurately?
There are probably many ways, but, if you were drawing this shape, then how would you draw it accurately?
So that, if it was turned/spun around its axis, it would still look exactly the same.
(Hope I've explained that properly!)
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...Accurately?
There are probably many ways, but, if you were drawing this shape, then how would you draw it accurately?
So that, if it was turned/spun around its axis, it would still look exactly the same.
(Hope I've explained that properly!)
Rik, this appears to be a constant breadth rotor of degree 3.
If it is symmetrical on rotation of 120deg either way then it is a equilateral triangle where the arcs between vertices are circular with a radius of a triangle side.
The cleanest Xara way I can use is to a create circle.
Clone this twice more and position so the circumference of one cuts through the centres of the other two.
Finally select all three overlapping circles and Intersect all shapes.
The inner part is your shield.
Acorn
I would create one arc using an equilateral triangle for a guide. Duplicate and rotate the the arc and then use the shape tool to connect the arcs.
Quick shape>triangular shape>ctrl+drag in place>Select polygons+starredshapes+rounded corners
Drag innermost handles outwards
Drag corners to create sharp corner
Drag other side handles towards the corner to create a smoother curve
Attachment 122236
Hi Rik, leaving aside the many ways to draw it the next problem is:
By axis I assume you mean centre. Unfortunately Xara can sometimes miss interprets the centre and this can lead to odd unwanted effects. Xara appears to determine the centre of rotation as a point half the height and half the width. This is very rarely the case.Quote:
So that, if it was turned/spun around its axis, it would still look exactly the same.
I'll expand further should you require ;)
Especially true with triangles.
Acorn, your method is very simple, quick and precise.=D>
No, Egg.
You don't have to explain any further. I know exactly what you mean, as the attached pic shows.
What I was trying to say was that when the shape is turned/spun, all the sides should be exactly the same.
Attachment 122238